The perimeters of square region Z and triangular region S are in a ratio of 1:2. If all the sides of triangular region S are equal then what is the ratio of the area of square region Z to the area of triangular region S?
A. \( \frac{5}{16\sqrt{2}} \)
B. \( \frac{7}{15\sqrt{2}} \)
C. \( \frac{7}{16\sqrt{3}} \)
D. \( \frac{7}{15\sqrt{3}} \)
E. \( \frac{9}{16\sqrt{3}} \)
Show the answer
Correct Answer: E.
