An object thrown directly upward is at a height of h feet after t seconds, where h = –16(t − 3)² + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height?
An object thrown directly upward is at a height of h feet after t seconds, where h = –16(t − 3)2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height? A. 6 B. 86 C. 134 D. 150 E. 166 Correct Answer: B Full explanation coming soon. Send us a note if you’d like […]